Equilibriums

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Ions and compounds are in equilibriums with each other. A typical equilibrium is the one between ammonia (NH3) and ammonium (NH4+) discussed in the section about pKa and Ka. These types of equilibriums are dependent on pH.

pH determines how much of a compounds or an ion in an equilibrium is dissociated. A simple example is already given in the pKa / Ka section, so here's a better one:

Consider the equilibrium between carbonic acid, bicarbonate and carbonic ion: H2CO3, HCO3- and CO32-. First of all it should be noted that only approximately 1/400 of the carbonic acid H2CO3 is on the form H2CO3. The rest is on the form CO2.

For this reason the carbonic acid in the "inorganic carbon equilibrium" is often denoted CO2* even though it at first sight seems unreasonable that CO2* can dissociate into HCO3-.

To calculate the concentration of individual species in the equilibrium one first have to introduce a variable denoting the sum of concentrations of CO2*, HCO3- and H2CO3. This variable should be called TIC - a shortcut for Total Inorganic Carbon.

TIC = [CO2*] + [HCO3-] + [CO32-]

If we start by finding the [CO2*], CO2* should be isolated in the above equation. By rearranging the equation above to:

TIC = [CO2*]. (1+ [HCO3-] / [CO2*] + [CO32-] / [CO2*])

If both sides are divided by (1+ [HCO3-] / [CO2*] + [CO32-] / [CO2*]) we get that:

[CO2*] = TIC / (1+ [HCO3-] / [CO2*] + [CO32-] / [CO2*])

To move on with this equation and to see how it depend on [H+] we introduce [H+] in the denominator:

[CO2*] = TIC / (1+ [HCO3-].[H+] / [CO2*].[H+] + [CO32-] / [CO2*])

At this point it is necessary to recall the definition of the dissociation constant. A more detailed explanation on this subject can be found on the site about pKa and Ka.

The ionisation constant of CO2* is [H+].[HCO3-]/[CO2*]

This ionisation constant can be substituted into denominator of the equation for TIC:

[CO2*] = TIC / (1 + Ka(CO2*) / [H+] + [CO32-] / [CO2*])

The calculation is not finished yet. [CO32-] and [CO2*] are not known.

They cannot be substituted the same way as before. However, the ionisation constant of HCO3- is [H+].[CO32-]/[HCO3-].

If this, the ionisation constant of HCO3- is multiplied by the ionisation constant of CO2* we get that:

Ka(HCO3-).Ka(CO2*)=[H+].[HCO3-]/[CO2*] . [H+].[CO32-]/[HCO3-] = [H+]2.([CO32-] / [CO2*]).

But this is the same as saying that:

Ka(CO2*).Ka(HCO3-) / [H+]2 = [CO32-] / [CO2*]

This can be substituted into the equation for the [CO2*] from before:

[CO2*] = TIC / (1 + Ka(CO2*) / [H+] + Ka(HCO3-).Ka(CO2*) / [H+]2)


Web resources

Theory about chemical equilibriums
Wikipedia equilibriums
A complete e-book about equilibriums (free)